Blog of RuSun

\begin {array}{c} \mathfrak {One Problem Is Difficult} \\\\ \mathfrak {Because You Don't Know} \\\\ \mathfrak {Why It Is Diffucult} \end {array}

线段树合并模板

树上问题。

路径转化为树上差分,每个点开一个权值线段树,最后计算答案时将子树信息合并。

查看代码
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#include <cstdio>
#include <vector>
using namespace std;
template <class Type>
void read(Type &x)
{
char c;
bool flag = false;
while ((c = getchar()) < '0' || c > '9')
c == '-' && (flag = true);
x = c - '0';
while ((c = getchar()) >= '0' && c <= '9')
x = (x << 3) + (x << 1) + c - '0';
if (flag) x = ~x + 1;
}
template <class Type, class ...rest>
void read(Type &x, rest &...y) { read(x), read(y...); }
template <class Type>
void write(Type x)
{
if (x < 0) putchar('-'), x = ~x + 1;
if (x > 9) write(x / 10);
putchar(x % 10 + '0');
}
const int N = 1e5 + 10, M = 8e6 + 10, K = 20;
vector <int> g[N];
int n, m, d[N], p[N];
int stmp, id[N], lg[N << 1], st[N << 1][K];
void dfs (int x)
{
st[id[x] = ++stmp][0] = x;
for (int i : g[x]) if (i ^ p[x])
{
d[i] = d[p[i] = x] + 1;
dfs(i);
st[++stmp][0] = x;
}
}
int dmin (int a, int b) { return d[a] < d[b] ? a : b; }
void init()
{
dfs(1);
for (int i = 2; i <= stmp; ++i) lg[i] = lg[i >> 1] + 1;
for (int k = 1; 1 << k <= stmp; ++k)
for (int i = 1; i + (1 << k) - 1 <= stmp; ++i)
st[i][k] = dmin(st[i][k - 1], st[i + (1 << k - 1)][k - 1]);
}
int lca (int a, int b)
{
a = id[a], b = id[b];
if (a > b) swap(a, b);
int k = lg[b - a + 1];
return dmin(st[a][k], st[b - (1 << k) + 1][k]);
}
struct Node
{
int l, r, v, p;
} tr[M];
int idx;
void pushup (int x)
{
int k = tr[tr[x].l].v >= tr[tr[x].r].v ? tr[x].l : tr[x].r;
tr[x].v = tr[k].v, tr[x].p = tr[k].p;
}
void modify (int &x, int t, int k, int l = 1, int r = 1e5)
{
if (!x) x = ++idx;
if (l == r) return tr[x].v += k, tr[x].p = t, void();
int mid = l + r >> 1;
t <= mid ? modify(tr[x].l, t, k, l, mid) : modify(tr[x].r, t, k, mid + 1, r);
pushup(x);
}
int merge (int x, int y, int l = 1, int r = 1e5)
{
if (!x || !y) return x | y;
if (l == r) return tr[x].v += tr[y].v, x;
int mid = l + r >> 1;
tr[x].l = merge(tr[x].l, tr[y].l, l, mid);
tr[x].r = merge(tr[x].r, tr[y].r, mid + 1, r);
pushup(x);
return x;
}
void calc (int x)
{
for (int i : g[x]) if (i ^ p[x])
calc(i), merge(x, i);
}
int main ()
{
read(n, m);
idx = n;
for (int i = 1, a, b; i < n; ++i)
{
read(a, b);
g[a].push_back(b), g[b].push_back(a);
}
init();
for (int i = 1, a, b, c; i <= m; ++i)
{
read(a, b, c);
int t = lca(a, b);
modify(a, c, 1), modify(b, c, 1);
modify(t, c, -1), modify(p[t], c, -1);
}
calc(1);
for (int i = 1; i <= n; ++i)
write(tr[i].v ? tr[i].p : 0), puts("");
return 0;
}