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\begin {array}{c} \mathfrak {One Problem Is Difficult} \\\\ \mathfrak {Because You Don't Know} \\\\ \mathfrak {Why It Is Diffucult} \end {array}

P5459 [BJOI2016]回转寿司

P5459 [BJOI2016]回转寿司

求多少个 $l, r$ 满足 $L\le s _r - s _ l \le R$ 。

查看代码
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#include <cstdio>
#include <algorithm>
using namespace std;
typedef long long LL;
const int N = 1e5 + 10;
int n, L, R;
LL ans, s[N];
void cdq(int l, int r)
{
if (l == r)
return;
int mid = l + r >> 1;
cdq(l, mid);
cdq(mid + 1, r);
int hd = l, tl = l - 1;
for (int i = mid + 1; i <= r; i++)
{
while (tl + 1 <= mid && s[i] - s[tl + 1] >= L)
tl++;
while (hd <= mid && s[i] - s[hd] >= R)
hd++;
ans += tl - hd + 1;
}
sort(s + l, s + r + 1);
}
int main()
{
scanf("%d%d%d", &n, &L, &R);
for (int i = 1; i <= n; i++)
{
scanf("%lld", &s[i]);
s[i] += s[i - 1];
}
cdq(0, n);
printf("%lld", ans);
return 0;
}