Blog of RuSun

\begin {array}{c} \mathfrak {One Problem Is Difficult} \\\\ \mathfrak {Because You Don't Know} \\\\ \mathfrak {Why It Is Diffucult} \end {array}

P2762 太空飞行计划问题

P2762 太空飞行计划问题

最大权闭合子图。

查看代码
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#include <iostream>
#include <cstdio>
#include <queue>
#include <string>
#include <climits>
#define INF INT_MAX
using namespace std;
const int N = 6e4 + 10, M = 31e4 + 10;
int n, m, st, ed, tot, d[N], cur[N];
bool vis[N];
int idx = -1, hd[N], nxt[M], edg[M], wt[M];
bool bfs()
{
for (int i = st; i <= ed; i++)
d[i] = -1;
d[st] = 0;
cur[st] = hd[st];
queue <int> q;
q.push(st);
while (!q.empty())
{
int t = q.front();
q.pop();
for (int i = hd[t]; ~i; i = nxt[i])
if (d[edg[i]] == -1 && wt[i])
{
cur[edg[i]] = hd[edg[i]];
d[edg[i]] = d[t] + 1;
if (edg[i] == ed)
return true;
q.push(edg[i]);
}
}
return false;
}
int find(int x, int limit)
{
if (x == ed)
return limit;
int res = 0;
for (int i = cur[x]; ~i && res < limit; i = nxt[i])
{
cur[x] = i;
if (d[edg[i]] == d[x] + 1 && wt[i])
{
int t = find(edg[i], min(wt[i], limit - res));
if (!t)
d[edg[i]] = -1;
wt[i] -= t;
wt[i ^ 1] += t;
res += t;
}
}
return res;
}
int dinic()
{
int res = 0, flow;
while (bfs())
while (flow = find(st, INF))
res += flow;
return res;
}
void add (int x, int y, int z)
{
nxt[++idx] = hd[x];
hd[x] = idx;
edg[idx] = y;
wt[idx] = z;
}
void dfs (int x)
{
vis[x] = true;
for (int i = hd[x]; ~i; i = nxt[i])
if (!vis[edg[i]] && wt[i])
dfs(edg[i]);
}
int main ()
{
string str;
cin >> m >> n;
st = 0;
ed = n + m + 1;
for (int i = st; i <= ed; i++)
hd[i] = -1;
for (int i = 1, a, b = 0; i <= m; i++)
{
cin >> a;
tot += a;
add(st, i, a);
add(i, st, 0);
getline(cin, str);
for (int j = 1; j < str.size(); j++)
if (str[j] == ' ')
{
add(i, b + m, INF);
add(b + m, i, 0);
b = 0;
}
else
b = b * 10 + str[j] - '0';
add(i, b + m, INF);
add(b + m, i, 0);
b = 0;
}
for (int i = 1, a; i <= n; i++)
{
cin >> a;
add(i + m, ed, a);
add(ed, i + m, 0);
}
int res = dinic();
dfs(st);
for (int i = 1; i <= m; i++)
if (vis[i])
cout << i << ' ';
cout << endl;
for (int i = m + 1; i < ed; i++)
if (vis[i])
cout << i - m << ' ';
cout << endl << tot - res;
return 0;
}