Blog of RuSun

\begin {array}{c} \mathfrak {One Problem Is Difficult} \\\\ \mathfrak {Because You Don't Know} \\\\ \mathfrak {Why It Is Diffucult} \end {array}

P2761 软件补丁问题

P2761 软件补丁问题

简单的状态压缩。

查看代码
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#include <cstdio>
#include <queue>
using namespace std;
typedef long long LL;
template <class Type>
void read(Type &x)
{
char c;
bool flag = false;
while ((c = getchar()) < '0' || c > '9')
c == '-' && (flag = true);
x = c - '0';
while ((c = getchar()) >= '0' && c <= '9')
x = (x << 3) + (x << 1) + c - '0';
flag && (x = ~x + 1);
}
template <class Type>
void write(Type x)
{
x < 0 && (putchar('-'), x = ~x + 1);
x > 9 && (write(x / 10), 0);
putchar(x % 10 + '0');
}
const LL inf = 1e18;
const int N = 20, M = 110, K = 1 << 20;
bool vis[K];
LL d[K];
int n, m, b1[M], b2[M], f1[M], f2[M], wt[M];
int main()
{
read(n), read(m);
for (int i = 1; i <= m; i++)
{
read(wt[i]);
static char str[N + 10];
scanf("%s", str);
for (int j = 0; j < n; j++)
{
str[j] == '+' && (b1[i] |= 1 << j);
str[j] == '-' && (b2[i] |= 1 << j);
}
scanf("%s", str);
for (int j = 0; j < n; j++)
{
str[j] == '+' && (f2[i] |= 1 << j);
str[j] == '-' && (f1[i] |= 1 << j);
}
}
for (int i = 0; i < (1 << n); i++)
d[i] = inf;
d[(1 << n) - 1] = 0;
queue<int> q;
q.push((1 << n) - 1);
vis[(1 << n) - 1] = true;
while (!q.empty())
{
int t = q.front();
q.pop();
vis[t] = false;
for (int i = 1; i <= m; i++)
if ((t & b1[i]) == b1[i] && (t & b2[i]) == 0)
{
int j = t & (~f1[i]) | f2[i];
if (d[t] + wt[i] < d[j])
{
d[j] = d[t] + wt[i];
if (!vis[j])
{
q.push(j);
vis[j] = true;
}
}
}
}
write(d[0] == inf ? 0 : d[0]);
return 0;
}