Blog of RuSun

\begin {array}{c} \mathfrak {One Problem Is Difficult} \\\\ \mathfrak {Because You Don't Know} \\\\ \mathfrak {Why It Is Diffucult} \end {array}

P2468 [SDOI2010]粟粟的书架

P2468 [SDOI2010]粟粟的书架

第一部分暴力二维前缀和。

第二部分主席树,很好理解。

遇到了一个玄学问题,尚未解决。

UPD:我太菜了,数组大小算错了,结果开了 $O2$ 竟然有神奇的效果,导致把我带向了错误的方向。

查看代码
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#include <cstdio>
#include <algorithm>
using namespace std;
int n, m, q;
namespace BruteForce
{
const int N = 210;
int mn = 1000, mx = 1, w[N][N], c[1010][N][N], s[1010][N][N];
int main()
{
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++)
{
scanf("%d", &w[i][j]);
mx = max(mx, w[i][j]);
mn = min(mn, w[i][j]);
}
for (int k = 1; k <= 1000; k++)
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++)
{
c[k][i][j] = c[k][i - 1][j] + c[k][i][j - 1] - c[k][i - 1][j - 1] + (w[i][j] >= k);
s[k][i][j] = s[k][i - 1][j] + s[k][i][j - 1] - s[k][i - 1][j - 1] + (w[i][j] >= k ? w[i][j] : 0);
}
for (int l1, r1, l2, r2, h; q; q--)
{
scanf("%d%d%d%d%d", &l1, &r1, &l2, &r2, &h);
if (s[1][l2][r2] - s[1][l1 - 1][r2] - s[1][l2][r1 - 1] + s[1][l1 - 1][r1 - 1] < h)
{
puts("Poor QLW");
continue;
}
int l = mn, r = mx;
while (l < r)
{
int mid = l + r + 1 >> 1;
s[mid][l2][r2] - s[mid][l1 - 1][r2] - s[mid][l2][r1 - 1] + s[mid][l1 - 1][r1 - 1] < h ? r = mid - 1 : l = mid;
}
printf("%d\n", c[l][l2][r2] - c[l][l1 - 1][r2] - c[l][l2][r1 - 1] + c[l][l1 - 1][r1 - 1] - (s[l][l2][r2] - s[l][l1 - 1][r2] - s[l][l2][r1 - 1] + s[l][l1 - 1][r1 - 1] - h) / l);
}
return 0;
}
}
namespace PresidentTree
{
const int N = 5e5 + 10, M = 2e5 + 10;
struct Node
{
long long s;
int l, r, c;
} tr[M];
int idx;
int w[N], rt[N];
void pushup(int x)
{
tr[x].c = tr[tr[x].l].c + tr[tr[x].r].c;
tr[x].s = tr[tr[x].l].s + tr[tr[x].r].s;
}
void modify(int &x, int l, int r, int t, int k)
{
tr[++idx] = tr[x];
x = idx;
if (l == r)
{
tr[x].c++;
tr[x].s += k;
return;
}
int mid = l + r >> 1;
if (t <= mid)
modify(tr[x].l, l, mid, t, k);
else
modify(tr[x].r, mid + 1, r, t, k);
pushup(x);
}
int query(int x1, int x2, int l, int r, int h)
{
if (l == r)
return (h - 1) / l + 1;
int mid = l + r >> 1;
int rc = tr[tr[x2].r].c - tr[tr[x1].r].c;
long long rs = tr[tr[x2].r].s - tr[tr[x1].r].s;
if (h <= rs)
return query(tr[x1].r, tr[x2].r, mid + 1, r, h);
return query(tr[x1].l, tr[x2].l, l, mid, h - rs) + rc;
}
int main()
{
for (int i = 1; i <= m; i++)
{
scanf("%d", &w[i]);
rt[i] = rt[i - 1];
modify(rt[i], 1, 1000, w[i], w[i]);
}
for (int a, l, r, h; q; q--)
{
scanf("%d%d%d%d%d", &a, &l, &a, &r, &h);
if (tr[rt[r]].s - tr[rt[l - 1]].s < h)
puts("Poor QLW");
else
printf("%d\n", query(rt[l - 1], rt[r], 1, 1000, h));
}
return 0;
}
}
int main()
{
scanf("%d%d%d", &n, &m, &q);
if (n == 1)
return PresidentTree::main();
else
return BruteForce::main();
}