Blog of RuSun

\begin {array}{c} \mathfrak {One Problem Is Difficult} \\\\ \mathfrak {Because You Don't Know} \\\\ \mathfrak {Why It Is Diffucult} \end {array}

P2371 [国家集训队]墨墨的等式

P2371 [国家集训队]墨墨的等式

跳楼机的加强版。

查看代码
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#include <iostream>
#include <cstdio>
#include <queue>
#include <climits>
#define INF LLONG_MAX
using namespace std;
const int N = 5e5 + 10, M = 6e6 + 10;
int n, m, mi = INF, a[12];
long long l, r, ans, dis[N];
int idx, hd[N], nxt[M], edg[M], wt[M];
bool vis[N];
void spfa ()
{
dis[0] = 0;
queue <int> q;
q.push(0);
vis[0] = true;
while (!q.empty())
{
int t = q.front();
q.pop();
if (dis[t] == INF)
return;
vis[t] = false;
for (int i = hd[t]; i; i = nxt[i])
if (dis[t] + wt[i] < dis[edg[i]])
{
dis[edg[i]] = dis[t] + wt[i];
if (!vis[edg[i]])
{
q.push(edg[i]);
vis[edg[i]] = true;
}
}
}
}
void add (int x, int y, int z)
{
nxt[++idx] = hd[x];
hd[x] = idx;
edg[idx] = y;
wt[idx] = z;
}
int main ()
{
cin >> m >> l >> r >> n;
l--;
for (int i = 0; i < n; i++)
dis[i] = INF;
for (int i = 1, x; i < m; i++)
{
cin >> x;
for (int j = 0; j < n; j++)
add(j, (j + x) % n, x);
}
spfa();
for (int i = 0; i < n; i++)
{
if (r >= dis[i])
ans += (r - dis[i]) / n + 1;
if (l >= dis[i])
ans -= (l - dis[i]) / n + 1;
}
cout << ans;
return 0;
}